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2 I(-) ----> I2 + 2e |*3
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Cr2O7(2-) + 14H(+) + 6e + 6 I(-) ---->3 I2 + 6e + 2Cr(3+) + 7H2O
po dodaniu przeciwjonów otrzymamy
K2Cr2O7 + 7H2SO4 + 6 KI ---->3 I2 + Cr2(SO4)3 + 7H2O + 4K2SO4