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a=16[g] masa glinu
4+16[g]=20[g] masa stopu
(4/20)*100%=20%
100%-20%=80%
Miedz stanowi 20% masy stopu , a glin 80%
16/20 - 80/100
Miedź - 20% w stopie
Glin - 80% w stopie
Pozdrawiam!: )