Question

wyznacz liczbe a

a) 4/sqrt{63}-8/sqrt{28}+/sqrt{700}=a/sqrt{7}

b)

/sqrt{27}+/sqrt{108}-/sqrt{12}+/sqrt{75}=a/sqrt{3}

Answer 1

4√63-8√28+√700=a√7

12√7-16√7+10√7=a√7

6√7=a√7

a=6

 

 

√27+√108-√12+√75=a√3

3√3+6√3-2√3+5√3=a√3

12√3=a√3

a=12

Answer 2

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