February 2019 0 49 Report
Sprawdź, czy podane równości są tożsamościami trygonometrycznymi, wiedząc że \alpha \in (0^{\circ}, 90^{\circ})\cup (90^{\circ},180^{\circ}):

a) sin\alpha\cdot \frac{ctq\alpha}{cos\alpha}=1
b) sin\alpha + sin\alpha \cdot tg^2\alpha=\frac{tg\alpha}{cos\alpha}

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