Question

SPLDV metode substitusi

x-2y+1=0;2x+3y=12

Answer 1

x -  2y = -1
x         = 2y - 1

2x + 3y      = 12
4y - 2 + 3y = 12
7y - 2         = 12
7y              = 14
  y              = 2

x - 2y + 1 = 0
x - 4 + 1   = 0
x              = 3

x = 3
y = 2

Answer 2

x-2y+1 = 0 --> x = 2y-1

substitusi
2x+3y = 12
2(2y-1)+3y = 12
4y-2+3y = 12
7y = 12+2
7y = 14
  y = 2

x = 2y-1
x = 2.2-1
x = 4-1
x = 3