Soal no 8 mohon dibantu dengan caranya
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m=-1/4
y=4(x+1)^-1/2
m=y'=4(-1/2)(x+1)^-3/2
-1/4=(-2)/(x+1)^3/2
(x+1)^3/2=8
(x+1)^3 = 64
(x+1)^3=2^6
(x+1)^3=(2^2)^3
x+1=2^2
x+1=4
x=3
y=2
PGS:
y-y1=m(x-x1)
y-2=-1/4(x-3)
4y-8=-x+3
x+4y-11=0