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maka, f'(x) =.....?
penyelesaian :
u = 2x^2 - x - 3
u' = 4x - 1
v = 2x - 3
v' = 2
f'(x) = u'v - uv'/v^2
= 4x - 1 (2x - 3) - 2x^2 - x - 3 (2) / (2x - 3)^2
=(8x^2 - 12x - 2x + 3)-(4x^2- 2x) / (2x - 3)^2
=8x^2 - 14x + 3 - 4x^2 + 2x / (2x - 3)^2
= 4x^2 - 12x + 3 / (2x - 3)^2
mapel : matematika
kelas : 11
kategori : turunan & integral