Diketahui:
Segitiga 1:
a = 16 cm
t = 24 cm
segitiga 2:
a = 15 cm
t = √(16²+12²) = 20 cm
segitiga 3:
a = 8 cm
t = 24/2 = 12 cm
Ditanyakan:
Luas yg tdk diarsir
Jawab:
Luas yg tdk diarsir = L∆1 + L∆2 - 2.L∆3
= 1/2. a.t + 1/2. a.t - 2. 1/2. a.t
= 1/2. 16. 24 + 1/2. 15. 20 - 8. 12
= 192 + 150 - 96
= 246 cm²
Mapel: Matematika
Kelas: 7
Materi: Segitiga
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Diketahui:
Segitiga 1:
a = 16 cm
t = 24 cm
segitiga 2:
a = 15 cm
t = √(16²+12²) = 20 cm
segitiga 3:
a = 8 cm
t = 24/2 = 12 cm
Ditanyakan:
Luas yg tdk diarsir
Jawab:
Luas yg tdk diarsir = L∆1 + L∆2 - 2.L∆3
= 1/2. a.t + 1/2. a.t - 2. 1/2. a.t
= 1/2. 16. 24 + 1/2. 15. 20 - 8. 12
= 192 + 150 - 96
= 246 cm²
Mapel: Matematika
Kelas: 7
Materi: Segitiga