Question

Soal kimia no 6 & 7 please!! plus cara ya!!

Answer 1

Nomor 6 antiseptik ( fenol )
nomor 7.

CH3COOH + NaOH ---> CH3COONa
100ml 100ml 200ml
0,2M 0,2M 0,1M
m 20mmol 20mmol -
r 20mmol 20mmol 20mmol
s - - 20mmol


pOH = -log √kw/ka . M
= -log√10^-14/10^-5 . 10^-1
=-log√10^-10
=-log 10^-5
=5-1
=4
pH = 14-4 =10