Skróć ułamki.
9+6x+x²
x²-9
Rozwiąż równania:
a) (x-1)x² - 2x(x-1)+(x-1)=0
b) 9(x=2) - 6x(x+2) + (x+2)x²=0
Pomocy! :(
9+6x+x²/x²-9=x²+6x+9/(x-3)(x+3)=(x+3)²/(x-3)(x+3)=(x+3)/(x-3)
odp.(x+3)/(x-3)
a)(x-1)x²-2x(x-1)+(x-1)=0
x-1=0
x=1
x²=0
x=0
-2x=0
Opd. x=1, x=0
b)9(x+2)-6x(x+2)+(x+2)x²=0
x+2=0
x=-2
-6x=0
odp.x=-2, x=0
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9+6x+x²/x²-9=x²+6x+9/(x-3)(x+3)=(x+3)²/(x-3)(x+3)=(x+3)/(x-3)
odp.(x+3)/(x-3)
a)(x-1)x²-2x(x-1)+(x-1)=0
x-1=0
x=1
x²=0
x=0
-2x=0
x=0
x-1=0
x=1
x-1=0
x=1
Opd. x=1, x=0
b)9(x+2)-6x(x+2)+(x+2)x²=0
x+2=0
x=-2
-6x=0
x=0
x+2=0
x=-2
x+2=0
x=-2
x²=0
x=0
odp.x=-2, x=0