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m=(1+x)(1+x2)−1m=1+x1+x2-1
Expande (1+x)(1+x2)1+x1+x2
m=1+x2+x+x3−1m=1+x2+x+x3-1
Resta 11 de 11 para obtener 00.
m=x2+x+x3+0m=x2+x+x3+0
Suma x2x2 y 00 r x2x2.
m=x2+x+x3m=x2+x+x3
m=x2+x3+xm=x2+x3+x
x2x2 y x3x3.
m=x3+x2+x