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Aplicamos la formula
d(P1,P2) = √((X2-X1)² +(Y2-Y1)²) //X2 es x sub2 y asi para los demas
P1 =P= (3,y)
P2= R = (-4,1)
d(P1,P2) = √((X2-X1)² +(Y2-Y1)²)
13 = √((-4 -3)² +(1-y)²)
13² = (-4 -3)² +(1-y)²
13² = (- 7)² +(1-y)²
169-49 = (1-y)²
120 = (1-y)²
√120 = 1 -y
√(120) - 1 = -y
1- √120 = y
-9.955 = y ó 11.955 = y // las dos soluciones son validas
P= (3,-9.955 ) ó P =( 3, 11.955)
Prueba
13 = √((-4 -3)² +(1-y)²) tomando y = -9.955
13 = √((-4 -3)² +(1-(-9.955))²)
13 = √((- 7)² +(10.955))²)
13 = √(49 + 120)
13 = √169
13 = 13
13 = √((-4 -3)² +(1-y)²) tomando y = 11.955
13 = √((-4 -3)² +(1-11.955)²)
13 = √((- 7)² +(-10.955))²)
13 = √(49 + 120)
13 = √169
13 = 13