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entonces su numero consecutivo es "a+1"
(a*(a+1))-31=5*(a+a+1)
a^2+a-31=10a+5
a^2-9a-36=0
(a-12)(a+3)=0
a-12=0
a+3=0
a=12 v a=-3
X + 1 = Numero consecutivo
X(X+1) - 31= 5[X + (X +1)]
X² +X -31 = 5[2X + 1]
X² +X - 31 = 10X + 5
X² - 9X - 36 = 0; Donde a = 1; b = -9; c = - 36
X1 = [9 +15]/2 = 12
X2 = [9 - 15]/2 = - 3