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S5 = 5/2 (a+Un)
520 = 2,5 (30 + U5)
520/2,5 = 30 + U5
208 = 30 + U5
U5 = 208 - 30
U5 = 178
maka tali terpanjang adalaj 178 cm
U1 = a = 30 cm
Sn = n/2 (2a + (n-1 ) b )
S5 = 5/2 ( 2. 30 + ( 5-1) b )
520 = 5/2 ( 60 + 4 b)
520 = 150 + 10 b
10 b = 520 - 150
10 b = 370
b =370/ 10 = 37
U5 = a+ 4b = 30 + 4 ( 37) = 30 + 148 = 178