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ΔT= 100°C
Q= 135.000 J
Dit: C..? & kalor jenis besi..?
Peny: Q=C.ΔT ⇔ C= Q ÷ ΔT ⇒C=135.000 J ÷100°C ⇒ C= 1350 J/°C
Q= m.c.ΔT ⇔ c = Q÷ m.ΔT ⇒ c=135.000 J ÷ 3 kg. 100°C ⇒ 450 J/kg.°C