Question

Selesaikan bentuk integral dibawah ini dengan substitusi
Integral (x+1)(x²+2x-8)⁴ dx

Answer 1

Verified answer

InTegraL

Misal :
u = x² + 2x - 8
du/dx = 2x + 2 = 2(x + 1)
(x + 1) dx = 1/2 du

∫(x + 1)(x² + 2x - 8)^4 dx
= ∫u^4 . 1/2 du
= 1/2 . 1/5 . u^5 + C
= 1/10 (x² + 2x - 8)^5 + C

Answer 2

Verified answer

InTegral SubstituSi

∫ (x+1)(x² + 2x - 8)⁴ dx=

 = (x+1)/(2x +2) (1/5)  (x² + 2x  -8)⁵ + c
= (x+1) / 2(x+1)  (1/5) (x² + 2x - 8)⁵ + c
= (1/2)(1/5)(x² + 2x -8)⁵  + c
= 1/10 (x² + 2x - 8)⁵ + c
....