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◾ Materi : Medan Magnetik dan Induksi Elektromagnetik◾ Sub materi : Trafo
◾ Mapel : Fisika
Diketahui :
Vp = 200 v
Vs = 500 v
η = 80% = 0,8
Ip = 10 A
Ditanya :
Is = ?
Penyelesaian :
η = Ps/Pp
η = Vs. Is / Vp. Ip
0,8 = 500. Is / 200. 10
0,8 = 500Is /2000
500Is = 1600
Is = 3,2 A
Jadi, besarnya kuat arus sekunder adalah 3,2 A
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-vin