Sebuah rumah menggunakan alat alat listrik sbb: # 8 lampu msing2 15 wat menyala 12 jam sehari # 1 TV 100 W menyala rata rata 10 jam sehari # 1 lemari es 80 W rata rata menyala 18 jam sehari # 1 radio tape 50 W rata rata di gunakan 5 jam sehari # 1 setrika listrik 300 W di gunakan rata2 1 jam sehari
Hitunglah energi listrik dalam sehari dan energi listrik dalam 30 hari, serta harga langganan yang harus d bayar selama 1 bulan jika harga setiap kWh Rp500,00.
Hazato
Lampu = 8 x 15 x 12 = 1440 TV = 1 x 100 x 10 = 1000 Lemari Es = 1 x 80 x 18 = 1440 Radio Tape = 1 x 50 x 5 = 250 Setrika = 1 x 300 x 1 = 300 + 4430 x 30 hari = 132900 Wh = 132,9 kWh Biaya = 132,9 Wh x Rp 500 = Rp 66.450
maaf kalau salah...
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yangyingyungyengyong
Diket= n1= 8 P1= 15W t1= 12 jam n2= 1 P2= 100W t2= 10 jam n3= 1 P3= 80 W t3= 18 jam n4= 1 P4= 50W t4= 5 jam n5= 1 P5= 300 W t5= 1 jam 1kWh=Rp500; Dit= energi listrik selama 1 bulan ...? Jawab= W1= n1.P1.t1.b= 8.15.12.30 = 43200 W2= n2.P2.t2.b= 1.100.10.30= 30000 W3= n3.P3.t3.b= 1.80.18.30 = 43200 W4= n4.P4.t4.b= 1.50.5.30 = 75000 W5= n5.P5.t5.b= 1.300.1.30 = 90000 W total= W1+W2+W3+W4+W5 = 43200+30000+43200+75000+90000 W total= 281400Wh W total= 281,4 kWh harga listrik 1 Bulan= 281,4 x Rp500 =Rp 140.700;
TV = 1 x 100 x 10 = 1000
Lemari Es = 1 x 80 x 18 = 1440
Radio Tape = 1 x 50 x 5 = 250
Setrika = 1 x 300 x 1 = 300 +
4430 x 30 hari = 132900 Wh = 132,9 kWh
Biaya = 132,9 Wh x Rp 500 = Rp 66.450
maaf kalau salah...
n2= 1 P2= 100W t2= 10 jam
n3= 1 P3= 80 W t3= 18 jam
n4= 1 P4= 50W t4= 5 jam
n5= 1 P5= 300 W t5= 1 jam
1kWh=Rp500;
Dit= energi listrik selama 1 bulan ...?
Jawab=
W1= n1.P1.t1.b= 8.15.12.30 = 43200
W2= n2.P2.t2.b= 1.100.10.30= 30000
W3= n3.P3.t3.b= 1.80.18.30 = 43200
W4= n4.P4.t4.b= 1.50.5.30 = 75000
W5= n5.P5.t5.b= 1.300.1.30 = 90000
W total= W1+W2+W3+W4+W5
= 43200+30000+43200+75000+90000
W total= 281400Wh
W total= 281,4 kWh
harga listrik 1 Bulan= 281,4 x Rp500
=Rp 140.700;
Semoga membantu!!!