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d1 = 10 cm
dengan phytagoras
(1/2 d1)² + (1/2 d2)² = s²
(1/2 . 10)² + (1/2 . d2) = 13²
5² + (1/2 . d2) = 13²
25 + (1/2 . d2)² = 169
(1/2 . d2) = 169 - 25 = 144
1/2 . d2 = √144 = 12
d2 = 12 . 2 = 24 cm
Luas selubung prisma = keliling . tinggi
52 . t = 1040
t = 1040 / 52 = 20 cm
Volume = luas alas . tinggi
= d1.d2 / 2 . t
= 10 . 24 / 2 . 20
= 2400 cm