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½C = E/V
E₁ E₂
___ = ____
V₁ V₂
100 E₂
___ = ____
10 2
200 = 10 x E₂
E₂ = 200/10
E₂ = 20 mJ
Jadi, energi yang tersimpan dalam kapasitor sebesar 20 mJ