Question

Larutan NaOH 0,001 M sebanyak 10mL mempunyai nilai pH

Answer 1

M = 0,001 Molar

[OH⁻] = Molaritas x Valensi basa
[OH⁻] = 0,001 x 1
[OH⁻] = 0,001
[OH⁻] = 10⁻³

pOH = -log [OH⁻]
pOH = -log [10⁻³]
pOH = 3

pH = 14 - pOH
pH = 14 - 3
pH = 11

Jadi, ph larutan adalah 11