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m1 = 60 kg, t1 = 82°C
m2 = 300 kg, t2 = 10°C
Ditanya:
ta…..?
Jawab:
Q lepas = Q serap
m1 . c . ∆t = m2 . c . ∆t
60 . (t1-ta) = 300 . (ta- t2)
(82-ta) = 5 (ta-10)
82 – ta = 5 ta – 50
6ta = 132
ta = 22°C