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[OH]=akar(Kw*[garam]/ka)
=akar(10^-14 * 0,1/10^-5)
=akar(10^-10)
=10^-5
pOH=-log10^-5
=5
pH=14-5
=9
*[garam]=mol/volum total
=5/50
=0,1
[OH-] = akar Kw/KaxM
= akar 10^-14/10^-5x10^-1
=akar 10^-10
=10^-5
POH = -log [H+]
= -log 10^-5
= 5
PH = 14 - POH
= 14 - 5
= 9.