Question

Berapa mL larutan H2SO4 0,1 M diperlukan untuk menetralkan 200mL dalam NAOH yang pH-nya 12+ log5

Answer 1

² + 5 + 6 h
²+ 5 + 6 = + 2 . ( + 3)
+ 2 < + 3 = 2, 3, 5, 7, 11, … ∶

= 2
2 + 5 + 6 = + 2 . + 3 = 2 = 1 .2 = −2 . −1
h ∶
∶ + 2 . + 3 = 1 .2
+ 2 = 1 + 3 = 2
= 1 − 2 = 2 − 3
= −1 = −1 (h )

∶ + 2 . + 3 = −2 . −1
+ 2 = −2 + 3 = −1
= −2 − 2 = −1 − 3
= −4 = −4 (h )