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mol NH₄OH (basa lemah) = 100 x 0,1 = 10 mmol
Persamaan reaksi :
NH₄OH + HCl → NH₄Cl + H₂O
karena mol asam kuat = mol basa lemah, maka dua-duanya habis bereaksi. sehingga terbentuk sistem hidrolisis garam.
mol NH₄Cl (garam) = 10 mmol
M garam = mol/volume total
M garam = 10/200
M garam = 0,05 M
[H⁺] = √Kw/Kb • M garam
[H⁺] = √10⁻¹⁴/10⁻⁵ • 0,05
[H⁺] = √5 x 10⁻¹¹
[H⁺] = 7 x 10⁻⁶
pH = -log [H⁺]
pH = -log [7 x 10⁻⁶]
pH = 6 - log 7
Jadi, pH setelah reaksi adaah 6 - log 7
m 10 10 - -
r 10 10 10 10
s 0 0 10 10
M = 10/200 = 5 x 10^-2
H+ =
H+ =