Question

Sebanyak 1 ml KOH 1M ditambah air sehingga volume menjadi 1 liter. Larutan ini memiliki pH :
A. 8
B. 9
C. 10
D. 11
E. 12

Tolong bnget bantu, besok UTS...
thanks... :) :) :)

Answer 1

M₁ x V₁ = M₂ x V₂
1 x 1 = M₂ x 1000
M₂ = 1/1000
M₂ = 10⁻³ M

[OH⁻] = M x Valensi
[OH⁻] = 10⁻³ x 1
[OH⁻] = 10⁻³

pOH = -log [OH⁻]
pOH = -log [10⁻³]
pOH = 3

pH = 14 - pOH
pH = 14 - 3
pH = 11 (Jawaban D)

Answer 2

V1 M1 = V2 M2
1 . 1=1000 M2
M2 = 10^3 M
OH- = 10^-3
pOH = - log OH- = - log 10^-3 = 3
pH = 14-3=11