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1 M1 = 1000 10^-5
M1 = 10^-2 M
x = - log H+ = - log 10^- 2= 2 B
[H⁺] = 10⁻⁵
M = 10⁻⁵ Molar
Pakai rumus pengenceran :
M1 x V₁ = M₂ x V₂
10⁻⁵ x 1000 = M₂ x 1
M₂ = 0,01
[H⁺] = Molaritas x Valensi
[H⁺] = 0,01 x 1
[H⁺] = 10⁻²
pH = -log H⁺]
pH = -log [10⁻²]
pH = 2
Jadi, harga x adalah 2 (Jawaban A)