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Para un litro.
1l sol de reactivo
El factor 100g de reactivo / 90 gramos de NaOH es el factor pureza
Para 500 mL
0.5 L sol [tex] \frac{0.1mol NaOH}{1 L de sol} . \frac{40 g de NaOH}{1 mol NaOH} .\frac{100 g reactivo}{90g NaOH} = 2.22 g de reactivo