Mm C12H22O11 = 342 g/mol
n(moles) = masa / Mm
n = 20 g / 342 g/mol = 0.0584 mol
v = 500 mL / 1000 = 0,5 L
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Mm C12H22O11 = 342 g/mol
n(moles) = masa / Mm
n = 20 g / 342 g/mol = 0.0584 mol
v = 500 mL / 1000 = 0,5 L
M = Moles soluto / L soluciónM = 0.0584 mol / 0.5 L
M = 0.1168 mol/L