Salah satu persamaan asimtot hiperbola 9x²-4y²+8y-40=0 adalah…..
a. 3x-2y+1=0
b. 3x-2y+2=0
c. 9x-4y+4=0
d. 9x-4y+1=0
e. 9x+4y+1=0
sertain cara yaa :)
a. 3x-2y+1=0
b. 3x-2y+2=0
c. 9x-4y+4=0
d. 9x-4y+1=0
e. 9x+4y+1=0
sertain cara yaa :)
Takamori37
![9x^2-4y^2+8y-40=0 \\ 9x^2-4(y^2-2y)-40=0 \\ 9x^2-4(y^2-2y+1)-36=0 \\ 9x^2-4(y-1)^2=36 \\ \displaystyle \frac{x^2}{4}-\frac{(y-1)^2}{9}=1 \\ $Asimtot miringnya$ \\ \displaystyle (y-q)=\pm\frac{b}{a}(x-p) \\ \\ (y-1)=\pm\frac{3}{2}(x-0) \\ \\ 2y-2=\pm 3x \\ \pm 3x+2y-2=0 $ (Kalikan -1)$ \\ \mp3x-2y+2=0 $ (Ambil 3x yang positif) \\ 3x-2y+2=0 [B]](https://tex.z-dn.net/?f=9x%5E2-4y%5E2%2B8y-40%3D0+%5C%5C+9x%5E2-4%28y%5E2-2y%29-40%3D0+%5C%5C+9x%5E2-4%28y%5E2-2y%2B1%29-36%3D0+%5C%5C+9x%5E2-4%28y-1%29%5E2%3D36+%5C%5C+%5Cdisplaystyle+%5Cfrac%7Bx%5E2%7D%7B4%7D-%5Cfrac%7B%28y-1%29%5E2%7D%7B9%7D%3D1+%5C%5C+%24Asimtot+miringnya%24+%5C%5C+%5Cdisplaystyle+%28y-q%29%3D%5Cpm%5Cfrac%7Bb%7D%7Ba%7D%28x-p%29+%5C%5C+%5C%5C++%28y-1%29%3D%5Cpm%5Cfrac%7B3%7D%7B2%7D%28x-0%29+%5C%5C+%5C%5C+2y-2%3D%5Cpm+3x+%5C%5C+%5Cpm+3x%2B2y-2%3D0+%24++%28Kalikan+-1%29%24+%5C%5C+%5Cmp3x-2y%2B2%3D0+%24++%28Ambil+3x+yang+positif%29+%5C%5C+3x-2y%2B2%3D0+%5BB%5D "9x^2-4y^2+8y-40=0 \\ 9x^2-4(y^2-2y)-40=0 \\ 9x^2-4(y^2-2y+1)-36=0 \\ 9x^2-4(y-1)^2=36 \\ \displaystyle \frac{x^2}{4}-\frac{(y-1)^2}{9}=1 \\ $Asimtot miringnya$ \\ \displaystyle (y-q)=\pm\frac{b}{a}(x-p) \\ \\ (y-1)=\pm\frac{3}{2}(x-0) \\ \\ 2y-2=\pm 3x \\ \pm 3x+2y-2=0 $ (Kalikan -1)$ \\ \mp3x-2y+2=0 $ (Ambil 3x yang positif) \\ 3x-2y+2=0 [B]")
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