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Maka, f(-2) = 0
(-2)³ + p(-2)² - 3(-2) - 10 = 0
-8 + 4p + 6 - 10 = 0
4p - 12 = 0
4p = 12
p = 3
Maka polimomialnya adalah:
x³ + 3x² - 3x - 10 = 0
Jumlah akar:
x1 + x2 + x3 = -b/a
x1 + x2 + x3 = -3/1
x1 + x2 + x3 = -3