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x1=1
(a-1) .1 + (3a-1).1 -3a=0
a-1+3a-1-3a=0
a-2=0
a=2
x^2+5x-6=0
(x-1)(x+6)=0
akar lainnya tsb adalah x2=-6
untuk x = 1
(a - 1)(1)² + (3a - 1)(1) - 3a = 0
a - 1 + 3a - 1 - 3a = 0
a - 2 = 0
a = 2
persamaan menjadi : (2 - 1)x² + (3.2 - 1)x - 3(2) = 0
x² + 5x - 6 = 0
x1 + x2 = - b / a
1 + x2 = -5/1
1 + x2 = -5
x2 = - 5 - 1
x2 = - 6