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= [x² + x]³a
[ (3)² + 3 ] - [a² + a] = 10
(9 + 3) - a² - a - 10 = 0
-a² - a + 2 = 0
a² + a - 2 = 0
(a + 2)(a - 1) = 0
a = -2 atau a = 1