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Mr NaCl = 58,5
kenaikan titik didih ΔTb = molal x Kb x i
ΔTb = [massa NaCl/Mr] x [1000/massa air] x Kb x i
ΔTb = [5,85/58,5] x [1000/250] x 0,52 x 2
ΔTb = 0,1 x 4 x 1,04 = 0,416°C
sehingga titik didih Tb = 100° + 0,416° = 100,416°C
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