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Verified answer
DINAMIKA ROTASIsilinder pejal, menggelinding
h = 60 m
g = 9,8 m/s²
v = ___?
kecepatan sudut
v = ω R
→ ω = v / R
(jika tidak tergelincir/slip)
momen inersia
I = ½ m R²
Energi kinetik
Ek = Ek translasi + Ek rotasi
Ek = ½ m v² + ½ I ω²
Ek = ½ m v² + ½ (½ m R²) (v / R)²
Ek = ½ m v² + ¼ m v²
Ek = ¾ m v²
HKE
Ek di kaki = Ep di puncak
¾ m v² = m g h
v² = (4/3) g h
v = √( (4/3) g h)
v = √( (4/3) • 9,8 • 60)
v = √784 = 28 m/s ← jwb