Winda o ciężarze 15 kN porusza się w dół z przyspieszeniem 0,5 m/s2. Oblicz siłę wypadkową.
F = m x g
g = 9.8m/s^2
15 000 = 9.8m/9.8
m = 1530kg
a = 0.5m/s^2
Fw = m x a
Fw = 1530 x 0.5
Fw = 765N
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F = m x g
g = 9.8m/s^2
15 000 = 9.8m/9.8
m = 1530kg
a = 0.5m/s^2
Fw = m x a
Fw = 1530 x 0.5
Fw = 765N