kita gunakan hukum kekekalan energi mekanik:
EM(A) = EM(B)
EK(A) + EP(A) = EK(B) + EP(B)
0 + mgh(A) = EK(B) + mgh(B)
EK(B) = mgh(A) - mgh(B)
EK(B) = mg(h(A) - h(B))
EK(B) = 2.10.(2,4 - 1,2)
EK(B) = 24 J (Jawab: E)
##semoga dapat membantu ...
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kita gunakan hukum kekekalan energi mekanik:
EM(A) = EM(B)
EK(A) + EP(A) = EK(B) + EP(B)
0 + mgh(A) = EK(B) + mgh(B)
EK(B) = mgh(A) - mgh(B)
EK(B) = mg(h(A) - h(B))
EK(B) = 2.10.(2,4 - 1,2)
EK(B) = 24 J (Jawab: E)
##semoga dapat membantu ...