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hC = 1,25 m
vA = 0 maka EkA = 0
maka dari hukum kekekalan energi:
EkA + EpA = EkC + EpC
0 + mghA = EkC + mghC
EkC = mg(hA - hC)
EkC = (1)(10)(2 - 1,25) = 7,5 J