załóżmy , ze leniwiec porusza sie z predkością 3 cm/s. oblicz w jakim czasie pokona odległość 0,3 km.
0,3km = 300m = 30000cm
30000cm : 3 = 10000 sekund
0,3cm = 300m
300m = 30 000cm
30 000cm / 0,3cm = 10 000s
10 000s = 3h 46min 40s
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0,3km = 300m = 30000cm
30000cm : 3 = 10000 sekund
0,3cm = 300m
300m = 30 000cm
30 000cm / 0,3cm = 10 000s
10 000s = 3h 46min 40s