IQI=2^4=16
zd. A' polega na tym, ze wypadnie co najwyzej 1 orzel
IA'I=5 (r,r,r,r)(0,r,r,r)(r,0,r,r)(r,r,0,r)(r,r,r,))
IAI=16-5=11
P(A)=11/16
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IQI=2^4=16
zd. A' polega na tym, ze wypadnie co najwyzej 1 orzel
IA'I=5 (r,r,r,r)(0,r,r,r)(r,0,r,r)(r,r,0,r)(r,r,r,))
IAI=16-5=11
P(A)=11/16