Ilosc wszystkich zdarzen - Moc zbioru Omega
IQI=6*6=36
IAI= 6 (1,6)(6,1)(2,5)(5,2)(3,4)(4,3)
P(A)=6/36=1/6
omega=6²=36
A={1,6 2,5 3,4 4,3 5,2 6,1 }
A= 6
P(A)=A/omega
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Ilosc wszystkich zdarzen - Moc zbioru Omega
IQI=6*6=36
IAI= 6 (1,6)(6,1)(2,5)(5,2)(3,4)(4,3)
P(A)=6/36=1/6
omega=6²=36
A={1,6 2,5 3,4 4,3 5,2 6,1 }
A= 6
P(A)=A/omega
P(A)=6/36=1/6