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ax+by=ap+bq
misalnya: 3x-5y+2+0 sejajar (2,-1)
3x-5y= 3(2) 5(-1)
3x-5y =6+5
3x-5y=11
-rumus persamaan garis tegak lurus, syarat m1Xm2
misal: 4x+5y+20=0 tegak lurus (3,-2)
5x-4y+5(3)-4(-2)
5x-4y=15+8
5x-4y=23
rumusnya: y-y1=m(x-x1)
-rumus persamaan garis melalui 2 titik:
y - y1 = m ( x - x1 )y - y1 y - y1 = y2 - y1
- rumus gradien melalui gradien m
m=-koef x/koef y
semoga bermanfaat :)