Rozwiązywanie układów rónan metodą podstawiana:
u=4v
5u-v=10
3v=s
3v+s=24
2x-y=10
x+5y=-17
3m+n=9
2m-5m=-11
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u=4v
5u-v=10
u=4v
5*(4v)-v=10
u=4v
20v-v=10
u=4v
19v=10/:19
u=4v
v=10/19
u=4*10/19
v=10/19
u=40/19
v=10/19
u=22/19
v=10/19
3v=s
3v+s=24
s=3v
3v+3v=24
s=3v
6v=24/6
s=3v
v=4
s=3*4
v=4
s=12
v=4
a) u=4v
5u-v= 10
u=4v
5*4v-v=10
u=4v
20v-v=10
u=4v
19v=10
u=4v
v=10/19=5/8
u= 4* 5/8= 2,5
b)3v=s
3v+s=24
s=3v
3v+3v=24
s=3v
6v=24
s=3v
v=4
s=3*4=12
v=4
c)2x-y=10
x+5y= -17
2x-y=10
x= -17 - 5y
2(-17 - 5y)-y=10
x= -17 -5y
-34-10y-y=10
x= -17-5y
-11y=44
x= -17-5y
y= -4
x= -17-5*(-4)= 20-17=3
d) 3m+n=9
2m-5n=-11
n=9-3m
2m-5(9-3m)=-11
n=9-3m
2m-45+15m=-11
n=9-3m
17m=34
n=9-3m
m=2
n=9-3*2=3
m=2