rozwiąz zadanie ułamki (6 całych 7 25-1cała4 20)-(8 całych 1 16-7 całych 24 48=
(4 całe 2 15+5calych 10 20 )-(2 całe 19 24-1cała1 5)=
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1) ( 6⁷/₂₅ - 1⁴/₂₀) - (8¹/₁₆ - 7 ²⁴/₄₈) = ( 6⁷/₂₅ - 1⅕) - ( 8¹/₁₆ - 7½ ) = (6⁷/₂₅ - 1⁵/₂₅) - (8¹/₁₆ - 7⁸/₁₆) =
= 5²/₂₅ - (7¹⁷/₁₆ - 7⁸/₁₆) = 5²/₂₅ - ⁹/₁₆ = 5³²/₄₀₀ - ²²⁵/₄₀₀ = 4⁴³²/₄₀₀ - ²²⁵/₄₀₀ = 4 ²⁰⁷/₄₀₀
2) (4²/₁₅ + 5¹⁰/₂₀) - (2¹⁹/₂₄ - 2⅕ ) = (4²/₁₅ + 5½) - (2⁹⁵/₁₂₀ - 2²⁴/₁₂₀ ) = (4 ⁴/₃₀ + 5 ¹⁵/₃₀) - ⁷¹/₁₂₀ =
= 9¹⁹/₃₀ - ⁷¹/₁₂₀ = 9⁷⁶/₁₂₀ - ⁷¹/₁₂₀ = 9⁵/₁₂₀ = 9¹/₂₄