Rozwiąz układ równań x + 2y = 3 metodą podstawiania.
2x + y = 12
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x+2y=3
2x+y=12
x=3-2y
2(3-2y)+y=12
6-4y+y=12
-3y=6 |:(-3)
y=-2
2x+(-2)=12
2x=14 |:2
x=7
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x+2y=3
2x+y=12
x=3-2y
2(3-2y)+y=12
6-4y+y=12
-3y=6 |:(-3)
y=-2
2x+(-2)=12
2x=14 |:2
x=7
x=7
y=-2