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(x-3)²+1²=25
x²-6x+9+1=25
x²-6x-15=0
Δ=36+60=96
√Δ=√96=4√6
x1=6-4√6/2
x2=6+4√6/2
dobra ocena rzeby była
:)
(x-3)²+1²=25
x²-6x+9+1=25
x²-6x-15=0
Δ=36+60=96
√Δ=√96=4√6
x1=6-4√6/2
x2=6+4√6/2