rozwiąz równanie kwadratowe deltą:
a)X2-10x+4=0
b) X2-7x-8=0
a)
x² - 10x + 4 = 0
Δ = b² - 4ac
Δ = 10² - 4*4 = 100 - 16 = 84
√Δ = √84 = 2√21
x₁ = 1/2 (10 - 2√21) = 5 -√21
x₂ = 1/2 (10 + 2√21) = 5 + √21
b) x² - 7x - 8 = 0
Δ = 49 + 32 = 81
√Δ = 9
x₁ = (7 - 9 )/ 2 = -1
x₂ = (7 + 9 )/ 2 = 8
x²-10x+4=0
a=1
b=-10
c=4
Δ=b²-4ac
Δ=10²-4·1·4=100-16=84
√Δ=2√21
x₁=2√21-(-10)/2=√21+5
x₂=-2√21+10/2=-√21+5
b)
x²-7x-8=0
b=-7
c=-8
Δ=7²-4·1·(-8)=49+32=81
√Δ=9
x₁=9-(-7)/2=8
x₂=-9+7/2=-1
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a)
x² - 10x + 4 = 0
Δ = b² - 4ac
Δ = 10² - 4*4 = 100 - 16 = 84
√Δ = √84 = 2√21
x₁ = 1/2 (10 - 2√21) = 5 -√21
x₂ = 1/2 (10 + 2√21) = 5 + √21
b) x² - 7x - 8 = 0
Δ = 49 + 32 = 81
√Δ = 9
x₁ = (7 - 9 )/ 2 = -1
x₂ = (7 + 9 )/ 2 = 8
a)
x²-10x+4=0
a=1
b=-10
c=4
Δ=b²-4ac
Δ=10²-4·1·4=100-16=84
√Δ=2√21
x₁=2√21-(-10)/2=√21+5
x₂=-2√21+10/2=-√21+5
b)
x²-7x-8=0
a=1
b=-7
c=-8
Δ=b²-4ac
Δ=7²-4·1·(-8)=49+32=81
√Δ=9
x₁=9-(-7)/2=8
x₂=-9+7/2=-1