February 2019 0 34 Report
Rozwiąz nierowności:
a)2cos (x -  \frac{ \pi }{3} ) < 1 , x∈ <-2 \pi ; 2 \pi>
b)sin (x +  \frac{ \pi }{4} ) ≥  \frac{ \sqrt{2} }{2} , x∈ <- \pi ; 3 \pi >
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