Rozwiazac rownanie x^x^3=3 (x do potegi x do 3)
x^x^3 = 3
podstawiam :
z = x^3
x = z^⅓
(z^⅓)^z = 3
z^(z/3) = 3 I()³
z^z = 3³
z = 3
x³ = 3 I∛
x = ∛3
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x^x^3 = 3
podstawiam :
z = x^3
x = z^⅓
(z^⅓)^z = 3
z^(z/3) = 3 I()³
z^z = 3³
z = 3
x³ = 3 I∛
x = ∛3
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