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x²-3x-3=-2x+x²
-3x-3=-2x
-3=x
b)x² - 2x = x(x - 1)
x²-2x=x²-x
-2x=-x
x=0
x²-3x-3=-2x+x²
-3x-3=-2x
-x=3
x=-3
b)x² - 2x = x(x - 1)
x²-2x=x²-x
-2x=-x
-x=0
x=0
x²-3x-3=-2x+x²
x²-3x-3+2x-x²=0
-x=3 //×-1
x=-3
b)x² - 2x = x(x - 1)
x²-2x=x²-x
x²-2x-x²+x=0
-x=0 //×-1
x=0